How would you print just the 10th line of a file?
For example, assume that file.txt
has the following content:
Line 1 Line 2 Line 3 Line 4 Line 5 Line 6 Line 7 Line 8 Line 9 Line 10Your script should output the tenth line, which is:
Line 10
用脚本输出文件中的第10行
sed -n '10p' file.txt