UVa_489 - Hangman Judge

本文介绍了一个Hangman游戏胜负判断程序的设计与实现。通过输入单词和玩家的猜测序列,程序能够准确判断玩家是否获胜、失败或放弃游戏。文章详细解释了程序的工作原理,并提供了完整的源代码。

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 Hangman Judge 

In ``Hangman Judge,'' you are to write a program that judges a series of Hangman games. For each game, the answer to the puzzle is given as well as the guesses. Rules are the same as the classic game of hangman, and are given as follows:

  1. The contestant tries to solve to puzzle by guessing one letter at a time.
  2. Every time a guess is correct, all the characters in the word that match the guess will be ``turned over.'' For example, if your guess is ``o'' and the word is ``book'', then both ``o''s in the solution will be counted as ``solved.''
  3. Every time a wrong guess is made, a stroke will be added to the drawing of a hangman, which needs 7 strokes to complete. Each unique wrong guess only counts against the contestant once.

       ______   
       |  |     
       |  O     
       | /|\    
       |  |     
       | / \    
     __|_       
     |   |______
     |_________|
  4. If the drawing of the hangman is completed before the contestant has successfully guessed all the characters of the word, the contestant loses.
  5. If the contestant has guessed all the characters of the word before the drawing is complete, the contestant wins the game.
  6. If the contestant does not guess enough letters to either win or lose, the contestant chickens out.

Your task as the ``Hangman Judge'' is to determine, for each game, whether the contestant wins, loses, or fails to finish a game.

Input

Your program will be given a series of inputs regarding the status of a game. All input will be in lower case. The first line of each section will contain a number to indicate which round of the game is being played; the next line will be the solution to the puzzle; the last line is a sequence of the guesses made by the contestant. A round number of -1 would indicate the end of all games (and input).

Output

The output of your program is to indicate which round of the game the contestant is currently playing as well as the result of the game. There are three possible results:

You win.
You lose.
You chickened out.

Sample Input

1
cheese
chese
2
cheese
abcdefg
3
cheese
abcdefgij
-1

Sample Output

Round 1
You win.
Round 2
You chickened out.
Round 3
You lose.

题意:

输入一个单词和玩家的猜测,判定猜测,成功或者失败或者放弃。

注意:对于单词``book,如果猜出o,那book中的两个o都算猜中,再次猜o,book中无法找到o了。'

解题思路:

1. 设置win,lose两个变量,win=1表示赢,lose=1表示失败;

2. win=1,对应情况是:遍历完单词(猜出了每个字母);lose=1,对应的错误次数等于7次了;win=0,lose=0,那么就是放弃

代码如下:

#include<iostream>
#include<cstdio>
using namespace std;

string str1,str2;
int win,lose;
int cnt; //统计已经猜到字母的个数
int error;//统计猜错次数

bool guess(char c)
{
    int len,ok=0;
    len = str1.length();
    for(int i = 0;i<len;i++){
        if(c==str1[i]&&str1[i]!='0') { str1[i] = '0'; ok = 1; cnt++;}
    }
    if(cnt==len) {win = 1; return true;}
    if(ok) return true;//本次猜测成功
    else return false;
}
int main()
{
    //freopen("maze.txt","r",stdin);
    int n;
    while(cin>>n)
    {
        if(n==-1) break;
        cin>>str1>>str2;
        win = lose = cnt = error = 0;
        int len = str2.length();
        for(int i=0;i<len;i++){
            if(guess(str2[i])) {if(win==1) break;}
            else error++;
            if(error==7) { lose = 1; break;}
        }
        cout<<"Round "<<n<<endl;
        if(win==1) cout<<"You win."<<endl;
        else if(lose==1) cout<<"You lose."<<endl;
        else cout<<"You chickened out."<<endl;
    }
    return 0;
}

 

 

 

 

 

 

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