信号量：Semaphore:Release

最新推荐文章于 2025-04-30 15:36:35 发布

原创最新推荐文章于 2025-04-30 15:36:35 发布 · 434 阅读

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#semaphore #thread #object #class

本文通过C#示例代码展示了如何使用Semaphore类来控制多个线程的并发访问。具体实现中，创建了一个Semaphore实例限制同时运行的线程数，并通过WaitOne和Release方法确保线程按指定数量依次执行。

using System; using System.Threading; public class Example { private static Semaphore _pool; private static int _padding; public static void Main() { _pool = new Semaphore(0, 3); for (int i = 1; i <= 5; i++) { Thread t = new Thread(new ParameterizedThreadStart(Worker)); t.Start(i); } Thread.Sleep(500); Console.WriteLine("Main thread calls Release(3)."); _pool.Release(3); Console.ReadKey(); } private static void Worker(object num) { Console.WriteLine("Thread {0} begins " + "and waits for the semaphore.", num); _pool.WaitOne(); int padding = Interlocked.Add(ref _padding, 100); Console.WriteLine("Thread {0} enters the semaphore.", num); Thread.Sleep(1000 + padding); Console.WriteLine("Thread {0} releases the semaphore.", num); Console.WriteLine("Thread {0} previous semaphore count: {1}", num, _pool.Release()); } }