Bank Interest

该博客探讨了复利计算的原理,通过一个具体的例子展示了如何利用数学函数pow计算投资的未来价值。 FarmerJohn在银行存入了一笔钱,年利率为5%,本金5000,计划投资4年。通过每年复利计算,最终得出他在4年后将拥有6077美元。这个例子说明了复利在长期投资中的重要性。

Farmer John made a profit last year! He would like to invest it well but wonders how much money he will make. He knows the interest rate R (an integer between 0 and 20) that is compounded annually at his bank. He has an integer amount of money M in the range 100..1,000,000. He knows how many years Y (range: 0..400) he intends to invest the money in the bank. Help him learn how much money he will have in the future by compounding the interest for each year he saves. Print an integer answer without rounding. Answers for the test data are guaranteed to fit into a signed 32 bit integer.

Input

* Line 1: Three space-separated integers: R, M, and Y

Output

* Line 1: A single integer that is the number of dollars FJ will have after Y years.

Sample Input

5 5000 4

Sample Output

6077

Hint

INPUT DETAILS:

5% annual interest, 5000 money, 4 years

OUTPUT DETAILS:

Year 1: 1.05 * 5000 = 5250
Year 2: 1.05 * 5250 = 5512.5
Year 3: 1.05 * 5512.50 = 5788.125
Year 4: 1.05 * 5788.125 = 6077.53125
The integer part of 6077.53125 is 6077.

Sponsor

思路:数学函数pow(a,b)=a的b次方

#include <iostream>
#include <cmath>
using namespace std;
 
int main()
{
    int r, m, y;
    cin >> r >> m >> y;
    cout << (int)(m * pow(1 + r / 100.0, y)) << endl;
    return 0;
}

 

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