Wind_Desert的博客

通过数学方法自行推导了周期数列的傅里叶级数与有限数列的离散傅里叶变换

简单对数不等式的证明证明: 1n+1ln(1+1n)1n,n∈N+\frac{1}{n+1}令an=(1+1n)n,bn=(1+1n)n+1a_n=(1+\frac{1}{n})^n,b_n=(1+\frac{1}{n})^{n+1}，则 an=(1+1n)n=∑k=0nCkn1nk=1+∑k=1nn(n−1)…(n−k+1)k!1nk=1+1+12!(1−1n)+⋯+\beg