import random
# partition list L use the rightest element as pivot
def partition(L, left, right):
x = L[right]
i = left - 1
for j in range(left, right):
if L[j] < x:
i += 1
L[i], L[j] = L[j], L[i]
L[i + 1], L[right] = L[right], L[i + 1]
return i + 1
# random partition
def random_partition(L, left, right):
''' get a pivot figure in list L
the parameter left and right must be used in the random method
because the random method is called recursively
'''
r = random.randrange(left,right)
L[r], L[right] = L[right], L[r]
return partition(L, left, right)
# random quick sort
def random_quicksort(L, left, right):
if left < 0 or right > len(L):
return
if left < right:
q = random_partition(L, left, right)
#print q
random_quicksort(L, left, q - 1)
random_quicksort(L, q + 1, right)
# quick sort
def quicksort(L, left, right):
if left < 0 or right > len(L):
return
if left < right:
q = partition(L, left, right)
#print q
quicksort(L, left, q - 1)
quicksort(L, q + 1, right)
# select the kth number of the list L
def selectKth(L, left, right, k):
assert k > 0 and k < len(L), "k must less than the length of the list"
if left == right:
return L[left]
pivot = random_partition(L, left, right)
#pivot = partition(L, left, right)
d = pivot - left + 1
#print d
if k == d: # the pivot value is the answer
return L[pivot]
elif k < d:
return selectKth(L, left, pivot - 1, k)
else:
return selectKth(L, pivot + 1, right, k - d)
def main():
L = [1, 4, 3, 6, 5, 8, 7]
print 'The original list is: ', L
kth = selectKth(L, 0, 6, 1)
print 'The kth number is ', kth
random_quicksort(L, 0, 6)
print 'The sorted list is: ', L
if __name__ == '__main__':
main()

本文介绍了一种改进的快速排序算法——随机快速排序,并解释了如何使用此算法选择列表中的第k小元素。通过随机选择枢轴元素,提高了排序效率。此外,还详细阐述了选择特定元素的方法,提供了实现示例。
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