#include<stdio.h>
int main()
{
int m, n, yu, j, b;
int sum[100]={1,0};
int a = 0, t = 0;
scanf("%d %d", &m, &n);
for (int i = m; i <= n; i++) {
for (j = 2, b = 1; j < i; j++) {
yu = i % j;
if (yu == 0) {
sum[b] = j;
b++;
}
}
for (int k = 0; k < b; k++) {
a = a + sum[k];
}
if (a == i) {
printf("%d = ", a);
for (int l = 0; l < b - 1; l++) {
printf("%d + ", sum[l]);
}
printf("%d\n", sum[b-1]);
t++;
}
a = 0;
}
if (t == 0) {
printf("None");
}
}
7-45 找完数
最新推荐文章于 2025-03-11 09:00:00 发布