1、在tomcat中新建一个web应用(如名字为servlet0_1),然后在web应用中新建一个WEB-INF/classes目录。
2、在classes目录中新建一个servlet_1.java
package servletdemo
import java.io.*;
import java.servlet.*;
public class servlet_1 extends GenericServlet{
public void service (ServletRepuest reg, ServletResponse res) throws ServletException, java.io.IOException{
OutputStream out =res.getOutputStream();
out.write("hello servlet !".getByte());
}
}
3、set classpath=%classpath%;```````````````servlet.jar 编译servlet
4、在WEB-INF目录中新建web.xml配置文件,配置servlet 的对外访问路径
<?xml version='1.0' encoding='utf-8'?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<servlet>
<servlet-name>servlet_1</servlet-name>
<servlet-class>servletdemo.servlet_1</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>servlet_1</servlet-name>
<url-pattern>/servlet_1</url-pattern>
</servlet-mapping>
</web-app>
5、启动tomcat,访问