javaSE基础例题-求和问题_java es 求和运算-优快云博客

文章展示了五个Java方法，分别计算1-10、1-100内奇数和偶数的和，以及1-100之间的奇数和，通过for和while循环实现。

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//1-10的和
    public static void sum1(){
        int a = 0, b;
        for ( b = 1 ;b <= 10; b ++){
            a += b;

        }
        System.out.println(a);
    }

    //1-100所有偶数的和
    public static void sum2(){
        int a , b;
        for ( a = 0,b = 0;b <= 100;b +=2 ){
            a +=b;
        }
        System.out.println(a);

}

    //1-100所有奇数的和
    public static void sum3(){
        int a ,b;
        for (a = 0, b = 1; b <=100; b +=2 ){
            a +=b;
        }
        System.out.println(a);
    }

//1-10的和
    public static void one() {
        int i = 0, sum = 0;
        while (i <= 10) {
            sum += i;
            i++;
        }
        System.out.println(sum);
    }

    //1-100之间偶数的和
    public static void two(){
        int i = 0,sum = 0;
        while (i <= 100&&i % 2 ==0){
            sum += i;
            i += 2;
        }
        System.out.println(sum);
    }

    //1-100之间奇数的和
    public static void three(){
        int i = 1 , k = 0;
        while (i <= 100||i % 3 == 0){
            k +=i;
            i +=2;
        }
        System.out.println(k);
    }