How many prime numbers (java)

本文介绍了一种使用Java实现的素数计数器算法。该算法接收一系列正整数作为输入,并输出其中素数的数量。文章详细展示了如何通过优化的算法判断一个数是否为素数,以及如何使用Java的快速输入输出方法来提高程序效率。

How many prime numbers

题目链接
Give you a lot of positive integers, just to find out how many prime numbers there are.

Input

There are a lot of cases. In each case, there is an integer N representing the number of integers to find. Each integer won’t exceed 32-bit signed integer, and each of them won’t be less than 2.

Output

For each case, print the number of prime numbers you have found out.

Sample Input

3
2 3 4

Sample Output

2

题目分析

题目意思为给你n个数,有几个素数输出几
java快速输入输出方法链接

代码实现

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.io.StreamTokenizer;

public class Main {
	public static boolean ss(int x) {//判断素数函数
		if (x == 2 || x == 3)
			return true;
		if (x % 2 == 0 || x % 3 == 0)//加快判断
			return false;
		for (int i = 5; i <= Math.sqrt(x); i++) {//这里是i小于等于x的平方就可以判断x是否为素数了
			if (x % i == 0)
				return false;
		}
		return true;
	}

	public static void main(String[] args) throws IOException {
		StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
		PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));
		int n, s, t;
		while (in.nextToken() != StreamTokenizer.TT_EOF) {//判断文件是否输入完毕
			n = (int) in.nval;
			s = 0;
			for (int i = 0; i < n; i++) {
				in.nextToken();
				t = (int) in.nval;
				if (ss(t))
					s++;
			}
			out.println(s);
			out.flush();
		}
	}
}

案例演示

在这里插入图片描述

文件1:第一行 {“index”: 0, “prompt”: {“data”: [“Suppose a a and b b are different prime numbers greater than 2. How many whole-number divisors are there for the integer a ( 2 a + b ) − 2 a 2 + a b a(2a+b)−2a 2 +ab?\nPlease reason step by step, and put your final answer within \boxed{}.”], “system_prompt”: null, “raw_input”: {“problem”: “Suppose a a and b b are different prime numbers greater than 2. How many whole-number divisors are there for the integer a ( 2 a + b ) − 2 a 2 + a b a(2a+b)−2a 2 +ab?”, “solution”: “Distributing and combining like terms, we have a ( 2 a + b ) − 2 a 2 + a b = 2 a 2 + a b − 2 a 2 + a b = 2 a b a(2a+b)−2a 2 +ab=2a 2 +ab−2a 2 +ab=2ab. Now a a and b b are different prime numbers greater than 2, so 2 a b = 2 1 c d o t a 1 c d o t b 1 2ab=2 1 cdota 1 cdotb 1 has ( 1 + 1 ) ( 1 + 1 ) ( 1 + 1 ) = b o x e d 8 (1+1)(1+1)(1+1)= boxed8 divisors.”, “answer”: “8”, “subject”: “Number Theory”, “level”: 4, “unique_id”: “test/number_theory/1287.json”}}, “tags”: [“en”], “categories”: [“DeepSeekDistill”, “Math”], “task_type”: “math”, “weight”: 0.3333333333333333, “dataset_name”: “math_500”, “subset_name”: “default”} 文件2:第281行 {“problem”: “Suppose a a and b b are different prime numbers greater than 2. How many whole-number divisors are there for the integer a ( 2 a + b ) − 2 a 2 + a b a(2a+b)−2a 2 +ab?”, “solution”: “Distributing and combining like terms, we have a ( 2 a + b ) − 2 a 2 + a b = 2 a 2 + a b − 2 a 2 + a b = 2 a b a(2a+b)−2a 2 +ab=2a 2 +ab−2a 2 +ab=2ab. Now a a and b b are different prime numbers greater than 2, so 2 a b = 2 1 c d o t a 1 c d o t b 1 2ab=2 1 cdota 1 cdotb 1 has ( 1 + 1 ) ( 1 + 1 ) ( 1 + 1 ) = b o x e d 8 (1+1)(1+1)(1+1)= boxed8 divisors.”, “answer”: “8”, “subject”: “Number Theory”, “level”: 4, “unique_id”: “test/number_theory/1287.json”} 写一个脚本依据problem字段的值查找两个文件中的所有问题是否一致,对比两个文件中的problem是否相同,两个文件中的该部分内容并不在同一行,如果不一致输出不一样的内容并将打印内容输出为一个文件
最新发布
08-15
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