epoll实现http

import socket
import re
import select


def service_client(new_socket, request):
    """为这个客户端返回数据"""

    # 1. 接收浏览器发送过来的请求 ，即http请求  
    # GET / HTTP/1.1
    # .....
    # request = new_socket.recv(1024).decode("utf-8")
    # print(">>>"*50)
    # print(request)

    request_lines = request.splitlines()
    print("")
    print(">"*20)
    print(request_lines)

    # GET /index.html HTTP/1.1
    # get post put del
    file_name = ""
    ret = re.match(r"[^/]+(/[^ ]*)", request_lines[0])
    if ret:
        file_name = ret.group(