Codeforces Round #146 (Div. 2)A. Boy or Girl

最新推荐文章于 2022-05-04 15:08:44 发布

轻舟不载愁

最新推荐文章于 2022-05-04 15:08:44 发布

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分类专栏： codeforces 文章标签： C/C++

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博客讲述了主人公因网络交友经历，想出通过用户名判断用户性别的方法，即用户名中不同字符数量为奇数是男性，偶数是女性。还给出了输入用户名判断性别的示例及输出结果。

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Those days, many boys use beautiful girls’ photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.

But yesterday, he came to see “her” in the real world and found out “she” is actually a very strong man! Our hero is very sad and he is too tired to love again now. So he came up with a way to recognize users’ genders by their user names.

This is his method: if the number of distinct characters in one’s user name is odd, then he is a male, otherwise she is a female. You are given the string that denotes the user name, please help our hero to determine the gender of this user by his method.

Input
The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters.

Output
If it is a female by our hero’s method, print “CHAT WITH HER!” (without the quotes), otherwise, print “IGNORE HIM!” (without the quotes).

Examples
inputCopy
wjmzbmr
outputCopy
CHAT WITH HER!
inputCopy
xiaodao
outputCopy
IGNORE HIM!
inputCopy
sevenkplus
outputCopy
CHAT WITH HER!
Note
For the first example. There are 6 distinct characters in “wjmzbmr”. These characters are: “w”, “j”, “m”, “z”, “b”, “r”. So wjmzbmr is a female and you should print “CHAT WITH HER!”.

#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
#include<ctime>
#include<iostream>
#include<algorithm>
#include<map>
#include<stack>
#include<queue>
#include<vector>
#include<set>
#include<string>
#define ll long long
#define dd double
using namespace std;
int main() {
	ios::sync_with_stdio(false);
	map<char, ll> ma;
	string s; cin >> s;
	for (ll i = 0; i < s.size(); i++) {
		ma[s[i]]++;
	}
	if (ma.size() % 2 == 0) {
		cout << "CHAT WITH HER!" << endl;
	}
	else {
		cout << "IGNORE HIM!" << endl;
	}
}