C++ CodeForces-467A. George and Accommodation【练习题】

本文介绍了一个编程问题,任务是计算在给定的宿舍房间中,哪些房间可以容纳额外的两个人,即George和Alex。通过读取每个房间的当前入住人数和最大容量,程序将输出满足条件的房间数量。

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A. George and Accommodation
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.

George and Alex want to live in the same room. The dormitory has n rooms in total. At the moment the i-th room has pi people living in it and the room can accommodate qi people in total (pi ≤ qi). Your task is to count how many rooms has free place for both George and Alex.

Input
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of rooms.

The i-th of the next n lines contains two integers pi and qi (0 ≤ pi ≤ qi ≤ 100) — the number of people who already live in the i-th room and the room’s capacity.

Output
Print a single integer — the number of rooms where George and Alex can move in.

Examples
input
3
1 1
2 2
3 3
output
0
input
3
1 10
0 10
10 10
output
问题链接:
       http://codeforces.com/problemset/problem/467/A

问题简述:
       输入房间数,房间已有人数,跟房间容纳量,计算能再多容纳两人的房间个数有几个。

问题分析:
       根据房间数申请空间,然后分别输入房间已有人数,跟房间容纳量,计算还可以容纳人数>=2的房间数。

贴上代码↓↓↓

#include <iostream>

using namespace std;

void main()
{
	int n,s=0;
	cin >> n;
	int *pi = new int[n];
	int *qi = new int[n];
	for (int i = 0; i < n; i++)
	{
		cin >> *(pi + i) >> *(qi + i);
		if ((*(qi + i) - *(pi + i)) >= 2)
			s++;
	}
	delete []pi;
	delete []qi;
	cout << s;
}
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