Python获取文件路径的父级目录、文件名、扩展名

原创已于 2024-01-17 10:35:53 修改 · 1.5k 阅读

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#python #数学建模 #开发语言

于 2023-06-27 10:42:11 首次发布

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该代码示例展示了如何使用Python的os.path模块来获取路径的各个部分，包括父目录、完整文件名、文件名和扩展名。

import os


class SplitFilePath():

    @classmethod
    def dirname(cls, path):
        try:
            return os.path.dirname(path)
        except Exception as e:
            return None

    @classmethod
    def basename(cls, path):
        try:
            return os.path.basename(path)
        except Exception as e:
            return None

    @classmethod
    def basename_without_ext(cls, path):
        try:
            file_full_name = os.path.basename(path)
            return os.path.splitext(file_full_name)[0]
        except Exception as e:
            return None

    @classmethod
    def ext(cls, path):
        try:
            file_full_name = os.path.basename(path)
            return os.path.splitext(file_full_name)[1][1:]
        except Exception as e:
            return None



if __name__ == '__main__':
    text_file = r'F:\text\gold.txt'

    # 提取父目录
    print(SplitFilePath.dirname(text_file))
    # F:\text

    # 提取完整文件名
    print(SplitFilePath.basename(text_file))
    # gold.txt

    # 提取文件名
    print(SplitFilePath.basename_without_ext(text_file))
    # gold

    # 提取扩展名
    print(SplitFilePath.ext(text_file))
    # txt