mysql segmentation fault_命令行登录mysql报Segmentation fault错误是怎么回事

bash[root@localhost bin]# ./mysql -uroot -p

Enter password:

Welcome to the MySQL monitor. Commands end with ; or \g.

Your MySQL connection id is 8

Server version: 5.6.24 Source distribution

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affiliates. Other names may be trademarks of their respective

owners.

Segmentation fault

mysql版本是5.6.24

服务器是CentOS7.0

==========解决方法============

在源码包里,编辑文件 cmd-line-utils/libedit/terminal.c

把terminal_set方法中的 char buf[TC_BUFSIZE]; 这一行注释,再把 area = buf;改为 area = NULL;

更改后如下

cmakeprotected int

terminal_set(EditLine *el, const char *term)

{

int i;

/*char buf[TC_BUFSIZE];*/

char *area;

const struct termcapstr *t;

sigset_t oset, nset;

int lins, cols;

--phpfensi.com

(void) sigemptyset(&nset);

(void) sigaddset(&nset, SIGWINCH);

(void) sigprocmask(SIG_BLOCK, &nset, &oset);

area = NULL;

然后重新编译即可