Java多线程之线程通信之生产者消费者阻塞队列版

Java多线程之线程通信之生产者消费者传统版和阻塞队列版

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目录

1. 线程通信之生产者消费者传统版
2. 线程通信之生产者消费者阻塞队列版

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1. 线程通信之生产者消费者传统版

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题目： 一个初始值为零的变量，两个线程对其交替操作，一个加1一个减1，来五轮
1.代码实现

import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;

class ShareData {  //资源类
    private int number = 0;
    private Lock lock = new ReentrantLock();
    private Condition condition = lock.newCondition();

    public void increment() throws Exception {
        lock.lock();
        try {
            //1.判断
            while (number != 0) {
                //等待，不能生产
                condition.await();
            }
            //2.干活
            number++;
            System.out.println(Thread.currentThread().getName() + "\t" + number);
            //通知唤醒
            condition.signalAll();

        } catch (Exception e) {
            e.printStackTrace();
        } finally {
            lock.unlock();
        }
    }

    public void decrement() throws Exception {
        lock.lock();
        try {
            //1.判断
            while (number == 0) {
                //等待，不能生产
                condition.await();
            }
            //2.干活
            number--;
            System.out.println(Thread.currentThread().getName() + "\t" + number);
            //通知唤醒
            condition.signalAll();

        } catch (Exception e) {
            e.printStackTrace();
        } finally {
            lock.unlock();
        }
    }


}

/**
 * 题目：
 * 一个初始值为零的变量，两个线程对其交替操作，一个加1一个减1，来五轮
 * <p>
 * 1.      线程  操作（方法）  资源类
 * 2.      判断  干活  通知
 * 3.      防止虚假唤醒
 */
public class ProdConsumer_TraditionDemo {
    public static void main(String[] args) {
        ShareData shareData = new ShareData();

        new Thread(() -> {
            for (int i = 1; i <=5 ; i++) {
                try {
                    shareData.increment();
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        },"AA").start();

        new Thread(() -> {
            for (int i = 1; i <=5 ; i++) {
                try {
                    shareData.decrement();
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        },"BB").start();
    }
}

2.编译结果

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2. 线程通信之生产者消费者阻塞队列版

题目： 一个初始值为零的变量，两个线程对其交替操作，一个加1一个减1，来五轮
1.代码实现

import java.util.concurrent.ArrayBlockingQueue;
import java.util.concurrent.BlockingQueue;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.atomic.AtomicInteger;

class MyResource {
    private volatile boolean FLAG = true; //默认开启，进行生产+消费
    private AtomicInteger atomicInteger = new AtomicInteger();

    BlockingQueue<String> blockingQueue = null;

    public MyResource(BlockingQueue<String> blockingQueue) {
        this.blockingQueue = blockingQueue;
        System.out.println(blockingQueue.getClass().getName());
    }

    public void myProdu() throws Exception {
        String data = null;
        boolean retValue;
        while (FLAG) {
            data = atomicInteger.incrementAndGet() + "";
            retValue = blockingQueue.offer(data, 2L, TimeUnit.SECONDS);
            if (retValue) {
                System.out.println(Thread.currentThread().getName() + "\t 插入队列" + data + "成功");
            } else {
                System.out.println(Thread.currentThread().getName() + "\t 插入队列" + data + "失败");
            }
            try {
                TimeUnit.SECONDS.sleep(1);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
        System.out.println(Thread.currentThread().getName() + "\t 大老板叫停了，表示FLAG=false，生产动作结束");
    }

    public void myConsumer() throws Exception {
        String result = null;
        while (FLAG) {
            result = blockingQueue.poll(2L, TimeUnit.SECONDS);
            if (null == result || result.equalsIgnoreCase("")) {
                FLAG = false;
                System.out.println(Thread.currentThread().getName() + "\t 超过2秒钟没有取到蛋糕，消费退出");
                System.out.println();
                System.out.println();
                return;
            }
            System.out.println(Thread.currentThread().getName() + "\t 消费队列蛋糕" + result + "成功");
        }
    }

    public void stop()throws Exception{
        this.FLAG = false;
    }
}

/**
 *
 */
public class ProdConsumer_BlockQueueDemo {
    public static void main(String[] args) throws Exception {
        MyResource myResource = new MyResource(new ArrayBlockingQueue<>(10));

        new Thread(() -> {
            System.out.println(Thread.currentThread().getName() + "\t 生产线程启动");
            try {
                myResource.myProdu();
            } catch (Exception e) {
                e.printStackTrace();
            }
        }, "Prod").start();

        new Thread(() -> {
            System.out.println(Thread.currentThread().getName() + "\t 消费线程启动");
            System.out.println();
            System.out.println();
            try {
                myResource.myConsumer();
                System.out.println();
                System.out.println();
            } catch (Exception e) {
                e.printStackTrace();
            }
        }, "Consumer").start();

        try {
            TimeUnit.SECONDS.sleep(5);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        System.out.println();
        System.out.println();
        System.out.println();

        System.out.println("5秒钟时间到，大老板main线程叫停，活动结束");

        myResource.stop();
    }
}

2. 执行结果