判断循环字符串的简单方法
如果a和b是互为循环字符串
则a in b+b
n = int(input())
res = []
for _ in range(n):
res.append(input())
all_word = set()
suma = 0
def check(old,this):
if old in this+this and len(old)==len(this):
return True
else:
return False
for each in res:
for each_old in all_word:
if check(each_old,each)==True:
break
else:
all_word.add(each)
suma += 1
print(suma)