代码随想录算法训练营第十一天 | 20. 有效的括号、 1047. 删除字符串中的所有相邻重复项、150. 逆波兰表达式求值

第一题

题目描述:
   https://leetcode.cn/problems/valid-parentheses/
思路:
   具体代码如下:


class Solution:
    def isValid(self, s: str) -> bool:
        stack = list()

        for i in s:
            cond = i == '(' or i =='[' or i =='{'
            if not stack or cond:
                stack.append(i)
            else:
                top = stack[-1]

                if i == ')' and top == '(':
                    stack.pop()

                elif i == ']' and top == '[':
                    stack.pop()

                elif i == '}' and top == '{':
                    stack.pop()
                    
                else:
                    return False

        if len(stack) == 0:
            return True

        return False

if __name__ == '__main__':
    obj = Solution()
    s = '(])'
    print(obj.isValid(s))


第二题

题目描述:
   https://leetcode.cn/problems/remove-all-adjacent-duplicates-in-string/
思路:
   具体代码如下:

class Solution:
    def removeDuplicates(self, s: str) -> str:
        stack = list()
        for i in s:
            if stack and i == stack[-1]:
                stack.pop()
            else :
                stack.append(i)
           
        return "".join(stack)



if __name__ == '__main__':
    obj = Solution()
    s = 'abbaca'
    print(obj.removeDuplicates(s))

第三题

题目描述:
   https://leetcode.cn/problems/evaluate-reverse-polish-notation/
思路:
   具体代码如下:

 from typing import List
from operator import add, sub, mul

class Solution:
	op_map = {'+': add, '-': sub, '*': mul, '/': lambda x, y: int(x / y) }

	def evalRPN(self, tokens: List[str]) -> int:
		
		stack = list()
		
		for item in tokens:
			if item not in {'+', '-', '*', '/'}:
				stack.append(int(item))
			else:
				op2 = stack.pop()
				op1 = stack.pop()
				stack.append(self.op_map[item](op1, op2))

		return stack.pop()


if __name__ == '__main__':
    obj = Solution()
    token = ["10","6","9","3","+","-11","*","/","*","17","+","5","+"]
    print(obj.evalRPN(token))
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