Leetcode413. Arithmetic Slices

本文介绍了一种算法,用于计算给定数组中所有等差数列切片的数量。通过实例说明了如何实现这一功能,并给出了具体的代码示例。

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A sequence of number is called arithmetic if it consists of at least three elements and if the difference between any two consecutive elements is the same.

For example, these are arithmetic sequence:

1, 3, 5, 7, 9
7, 7, 7, 7
3, -1, -5, -9
The following sequence is not arithmetic.

1, 1, 2, 5, 7

A zero-indexed array A consisting of N numbers is given. A slice of that array is any pair of integers (P, Q) such that 0 <= P < Q < N.

A slice (P, Q) of array A is called arithmetic if the sequence:
A[P], A[p + 1], …, A[Q - 1], A[Q] is arithmetic. In particular, this means that P + 1 < Q.

The function should return the number of arithmetic slices in the array A.

Example:

A = [1, 2, 3, 4]

return: 3, for 3 arithmetic slices in A: [1, 2, 3], [2, 3, 4] and [1, 2, 3, 4] itself.

其实就找规律的题,结果就是对于n的等差数列

public int numberOfArithmeticSlices(int[] A) {  
        if(A.length < 3) return 0;  
        int result = 0, start = -1;  
        for(int i = 1; i < A.length - 1; i ++){  
            if(A[i] - A[i-1] == A[i+1] - A[i]){  
                if(start == -1) start = i-1;  
            }else{  
                if(start != -1) {  
                    result += (i - start) * (i - start - 1) / 2;  
                    start = -1;  
                    i += 1;  
                }  
            }  
        }  
        if(start != -1) result += (A.length-1-start)*(A.length-start-2)/2;  
        return result;  
    } 
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