经典数据结构之栈的应用-迷宫问题

        栈是一种常用的数据结构，有着广泛的应用，例如走迷宫，八皇后问题，树的前序遍历，数学公式计算等等。以下是走迷宫问题代码

// Queen.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#define LEFT 0
#define RIGHT 1
#define UP 2
#define DOWN 3

#define VISITED 10 //如果走过，则标记为VISITED
#define UNVISITED 9//初始都为UNVISITED

//4个行进方向
typedef struct direction
{
    int x;
    int y;
}DIR;

//坐标点定义
typedef struct pos
{
    int pos_x;
    int pos_y;
}POSITION;

//路径
typedef struct Path
{
    POSITION point;
    int dir;
}PATH;

//stack
class Stack
{
private:
    int top;
    POSITION status[64];
    int m_maxNode;
public:
    Stack()
    {
        top=-1;
        m_maxNode=64;
        for(int i=0;i<64;i++)
            status[i].pos_x=status[i].pos_y=-1;
    }

    int Push(POSITION point)
    {
        if(top>=m_maxNode-1)
            return 1;//over flow!
        else
            status[++top]=point;
        return 0;
    }

    int Pop(POSITION *out)
    {
        if(top<0)
            return 1;
        out->pos_x=status[top].pos_x;
        out->pos_y=status[top--].pos_y;
        return 0;
    }

    int IsEmpty()
    {
        if(top==-1) return 1;
        else
            return 0;
    }

};


class Queen
{
private:
    DIR dir[4];
    int m_MazeLength;
    int Maze[9][9];
    int m_mark[9][9];
    int m_Path[20];
    int m_index;
public:
    Queen()
    {
        dir[LEFT].x=-1;
        dir[LEFT].y=0;

        dir[RIGHT].x=1;
        dir[RIGHT].y=0;

        dir[UP].x=0;
        dir[UP].y=-1;

        dir[DOWN].x=0;
        dir[DOWN].y=1;

        m_MazeLength=8;

        int tempMaze[9][9]={
                            {1,1,1,1,1,1,1,1,1},
                            {1,0,0,0,0,0,0,0,1},
                            {1,1,1,1,1,1,1,0,1},
                            {1,0,0,0,0,0,0,0,1},
                            {1,0,1,1,1,1,1,1,1},
                            {1,0,0,0,0,1,0,0,1},
                            {1,0,1,0,0,0,0,1,1},
                            {1,0,0,0,1,0,0,0,1},
                            {1,1,1,1,1,1,1,1,1}
                            };
    
    for(int i=0;i<9;i++)
        for(int j=0;j<9;j++)
        {
            Maze[i][j]=tempMaze[i][j];
            m_mark[i][j]=UNVISITED;
        }
    }


    int GetPath();

    POSITION GetPosition(POSITION current,int dire)
    {
        POSITION temp;
        temp.pos_x=current.pos_x + dir[dire].x;
        temp.pos_y=current.pos_y+ dir[dire].y;
        return temp;

    }
};


int Queen::GetPath()
{

    Stack mazeStack;
    POSITION pos;
    pos.pos_x=1;
    pos.pos_y=1;
    mazeStack.Push(pos);
    m_mark[pos.pos_y][pos.pos_x]=VISITED;
    //迷宫栈不为空，则一直继续
    while(!mazeStack.IsEmpty())
    {
        POSITION currentpos;
        mazeStack.Pop(&currentpos);

        if(currentpos.pos_x==7 &&currentpos.pos_y==7)
        {
        
            return 0;
        }
            //向上通路
        POSITION pos_Up,pos_Down,pos_Left,pos_Right;
        pos_Up=GetPosition(currentpos,UP);
        pos_Down=GetPosition(currentpos,DOWN);
        pos_Left=GetPosition(currentpos,LEFT);
        pos_Right=GetPosition(currentpos,RIGHT);
        
        //up direction
        if(Maze[pos_Up.pos_y][pos_Up.pos_x]==0 && m_mark[pos_Up.pos_y][pos_Up.pos_x]==UNVISITED)
        {
            mazeStack.Push(pos_Up);
            m_mark[pos_Up.pos_y][pos_Up.pos_x]=VISITED;
        }

        //left direction
        if(Maze[pos_Left.pos_y][pos_Left.pos_x]==0 && m_mark[pos_Left.pos_y][pos_Left.pos_x]==UNVISITED)
        {
            mazeStack.Push(pos_Left);
            m_mark[pos_Left.pos_y][pos_Left.pos_x]=VISITED;
        }

        //down direction
        if(Maze[pos_Down.pos_y][pos_Down.pos_x]==0 && m_mark[pos_Down.pos_y][pos_Down.pos_x]==UNVISITED)
        {
            mazeStack.Push(pos_Down);
            m_mark[pos_Down.pos_y][pos_Down.pos_x]=VISITED;
        }

        //right direction
        if(Maze[pos_Right.pos_y][pos_Right.pos_x]==0 && m_mark[pos_Right.pos_y][pos_Right.pos_x]==UNVISITED)
        {
            mazeStack.Push(pos_Right);
            m_mark[pos_Right.pos_y][pos_Right.pos_x]=VISITED;
        }
        
    }

    return 1;
}



int main(int argc, char* argv[])
{
    Queen q;
    if(!q.GetPath())
        printf("you have Walked out from the maze successfully\n");
    else
        printf("No Path to walk out from the maze\n");
    return 0;
}

转载于:https://www.cnblogs.com/Winston/archive/2008/05/31/1211207.html