[LeetCode] Binary Tree Maximum Path Sum

本文提供了一个相对复杂的树问题解决方案,采用递归方式实现路径求和,巧妙地记录结果。通过具体代码展示了如何寻找树中最大路径之和。

A relatively difficult tree problem. Well, a recursive solution still gives clean codes. The tricky part of this problem is how to record the result. You may refer to this link for a nice solution. The code is rewritten as follows.

class Solution {
public:
    int maxPathSum(TreeNode* root) {
        sum = INT_MIN;
        pathSum(root);
        return sum;
    }
private:
    int sum;
    int pathSum(TreeNode* node) {
        if (!node) return 0;
        int left = max(0, pathSum(node -> left));
        int right = max(0, pathSum(node -> right));
        sum = max(sum, left + right + node -> val);
        return max(left, right) + node -> val;
    }
};

 

转载于:https://www.cnblogs.com/jcliBlogger/p/4703234.html

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