WPF TreeView

1、不同于Windows Forms，当前WPF版本没有提供一个直接的方法可以把TreeView控件所有的节点都展开。一般来说，在WPF中有两种方法可以实现这个功能。第一种方法就像下面例子一样使用样式展开所有节点：

<Window xmlns= "http://schemas.microsoft.com/winfx/2006/xaml/presentation"       xmlns:x= "http://schemas.microsoft.com/winfx/2006/xaml"          x:Class= "ControlTest2.TreeViewTest"  Width= "500" >      <Window.Resources>          <XmlDataProvider x:Key= "treeData"  XPath= "*" >              <x:XData>                  <Items Name= "Items"  xmlns= "" >                      <Item1/>                      <Item2>                          <Item22/>                          <Item12/>                          <Item13>                              <Item131/>                              <Item131/>                          </Item13>                      </Item2>                  </Items>              </x:XData>            </XmlDataProvider>          <HierarchicalDataTemplate ItemsSource= "{Binding XPath=child::*}"    x:Key= "template" >              <TextBlock Name= "textBlock"  Text= "{Binding Name}" />          </HierarchicalDataTemplate>      </Window.Resources>      <WrapPanel>          <TreeView ItemTemplate= "{StaticResource template}"             ItemsSource= "{Binding Source={StaticResource treeData}}" >              <TreeView.ItemContainerStyle>                  <!--Using style setter to set  the TreeViewItem.IsExpanded property to true , this  will be applied        to all TreeViweItems when they are generated-->                  <Style TargetType= "{x:Type TreeViewItem}" >                      <Setter Property= "IsExpanded"  Value= "True" />                  </Style>              </TreeView.ItemContainerStyle>          </TreeView>      </WrapPanel> </Window>

　　参考：http://social.msdn.microsoft.com/Forums/zh-CN/wpfzhchs/thread/857fdaa9-5c67-4e0a-a1fd-037f72577c76

本文转自Work Hard Work Smart博客园博客，原文链接：http://www.cnblogs.com/linlf03/archive/2011/11/14/2248326.html，如需转载请自行联系原作者