求ax(2)+bx+c=0的解

最新推荐文章于 2023-01-08 15:45:23 发布

转载最新推荐文章于 2023-01-08 15:45:23 发布 · 260 阅读

本文详细介绍了如何使用Python的cmath和math模块解决二次方程，并通过输入系数来求解实数根和复数根。

import cmath
import math
import sys

def get_float(msg,allow_zero):
x = None
while x is None:
  try:
   x = float(input(msg))
   if not allow_zero and abs(x) < sys.float_info.epsilon:    #float_info.epsilon为接近0值的浮点数，因计算机浮点数只能无限接近0
    print("zero is not allowed")
    x = None
  except ValueError as err:
   print(err)
return x

print("ax2 + bx +c = 0")
a = get_float("enter a:",False)
b = get_float("enter b:",True)
c = get_float("enter c:",True)
x1 = None
x2 = None
discriminant = (b ** 2) - (4*a*c)
if discriminant == 0:
x1 = -(b/(2*a))
print(x1)
else:
if discriminant > 0:
  root = math.sqrt(discriminant)
else:
  root = cmath.sqrt(discriminant)   #cmath为复数形式
x1 = (-b+root)/(2*a)
x2 = (-b-root)/(2*a)
print(x1)
print(x2)