389. Find the Difference

最新推荐文章于 2024-09-29 07:15:00 发布

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最新推荐文章于 2024-09-29 07:15:00 发布

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原文链接：http://www.cnblogs.com/icysnow/p/8241429.html

本文介绍了一种通过异或操作高效找出两个字符串中新增字母的方法。该方法适用于当一个字符串是另一个字符串打乱顺序并添加了一个字母的情况。通过遍历两个字符串并应用异或操作，最终得出新增的字母。

Given two strings s and t which consist of only lowercase letters.

String t is generated by random shuffling string s and then add one more letter at a random position.

Find the letter that was added in t.

Example:

Input:
s = "abcd"
t = "abcde"

Output:
e

Explanation:
'e' is the letter that was added.

大致意思是这样，t是s的字母随机排列后多一个字母形成的新字符串。找出那个多的字母
用异或即可

 public char findTheDifference(String s, String t) {
        char result = 0;
        for (int i = 0; i < s.length(); i++) {
            result ^= s.charAt(i);
        }
        for (int i = 0; i < t.length(); i++) {
            result ^= t.charAt(i);
        }
        return result;
    }