uva - Digit Counting

最新推荐文章于 2023-02-06 16:25:28 发布

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最新推荐文章于 2023-02-06 16:25:28 发布

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文章标签： java

原文链接：http://www.cnblogs.com/ABC-00/p/5475442.html

本文介绍了一个有趣的数学作业游戏：从1写到N，统计每个数字0到9出现的次数。通过编写Java程序实现这一过程，帮助解决重复且枯燥的数学作业问题。

Trung is bored with his mathematics homeworks. He takes a piece of chalk and starts writing a sequence of consecutive integers starting with 1 to N <tex2html_verbatim_mark>(1 < N < 10000) <tex2html_verbatim_mark>. After that, he counts the number of times each digit (0 to 9) appears in the sequence. For example, with N = 13 <tex2html_verbatim_mark>, the sequence is:

12345678910111213

In this sequence, 0 appears once, 1 appears 6 times, 2 appears 2 times, 3 appears 3 times, and each digit from 4 to 9 appears once. After playing for a while, Trung gets bored again. He now wants to write a program to do this for him. Your task is to help him with writing this program.

Input

The input file consists of several data sets. The first line of the input file contains the number of data sets which is a positive integer and is not bigger than 20. The following lines describe the data sets.

For each test case, there is one single line containing the number N <tex2html_verbatim_mark>.

Output

For each test case, write sequentially in one line the number of digit 0, 1,...9 <tex2html_verbatim_mark>separated by a space.

Sample Input

2 
3 
13

Sample Output

0 1 1 1 0 0 0 0 0 0 
1 6 2 2 1 1 1 1 1 1

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        for (int i = 0; i < n; i++) {
            int m = in.nextInt();
            String s = "";
            for (int j = 1; j <= m; j++)
                s = s.concat(j + "");

            int[] ch = new int[10];
            for (int j = 0; j < s.length(); j++) {
                if (s.charAt(j) == '0')
                    ch[0]++;
                else if (s.charAt(j) == '1')
                    ch[1]++;
                else if (s.charAt(j) == '2')
                    ch[2]++;
                else if (s.charAt(j) == '2')
                    ch[2]++;
                else if (s.charAt(j) == '3')
                    ch[3]++;
                else if (s.charAt(j) == '4')
                    ch[4]++;
                else if (s.charAt(j) == '5')
                    ch[5]++;
                else if (s.charAt(j) == '6')
                    ch[6]++;
                else if (s.charAt(j) == '7')
                    ch[7]++;
                else if (s.charAt(j) == '8')
                    ch[8]++;
                else if (s.charAt(j) == '9')
                    ch[9]++;

            }
            for (int j = 0; j <= 9; j++) {
                System.out.print(ch[j]);
                if (j != 9)
                    System.out.print(" ");
            }
            System.out.println();
        }
    }
}