Software Testing 软件测试 HW2 Fault Error Failure

最新推荐文章于 2025-09-06 09:26:50 发布

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最新推荐文章于 2025-09-06 09:26:50 发布

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原文链接：http://www.cnblogs.com/wazxser/p/6481741.html

本文分析了两个程序中存在的缺陷，并为每个程序提供了不执行缺陷、执行缺陷但不导致错误状态、导致错误但非失败的测试案例。

There are two programs.

For program 1

 1 public int findLast(int[] x, int y){
 2   //Effects: If x==null throw NullPointerException
 3   //else return the index of the last elements
 4   //in x that equals y.
 5   //If no such elements exists, return -1
 6   for(int i=x.length-1; i>0; i--)
 7   {
 8       if(x[i] == y)
 9       {
10          return i;
11       }
12   }
13   return -1;
14 }

1、Identify Identify the fault.

　　　　i > 0, it should be i ≥ 0, the searching should be stopped at 0, not 1.

2、If possible, identify a test case that does not execute the fault. (Reachability) .

　　　　x=null, y=2

　　　　It will not execute the statement i>0 where the fault locates.

3、If possible, identify a test case that executes the fault, does not result in an error state.

　　　　x=[0, 1, 2], y=1

　　　　It will execute the statement i>0 and have the same state if i>0 is fixed by i≥0, not result in an error state.

4、If possible, identify a test case that results in an error, but not a failure.

　　　 x=[0, 1, 2], y=3

　　　　It will have an error state if the fault is fixed, but will have the same results, both -1.

For program 2

 1 public static int lastZero(int [] x){
 2   //Effects: ifx==null throw NullPointerException
 3   //else return the index of the LAST 0 in x.
 4   //Return -1 if 0 does not occur in x.
 5   for(int i=0; i<x.length; i++)
 6   {
 7        if(x[i] == 0)
 8        {
 9            return i;
10        }  
11   }  
12   return -1;
13 }