1005 Spell It Right (20)（20 point(s)）

最新推荐文章于 2022-06-17 10:43:23 发布

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最新推荐文章于 2022-06-17 10:43:23 发布

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原文链接：http://www.cnblogs.com/yoyo-sincerely/p/9265448.html

本文介绍了一个简单的程序设计问题，即计算一个非负整数各位数字之和，并将结果用英文单词输出。文章提供了完整的C++代码实现，包括如何转换数字为英文单词及处理边界条件。

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problem

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10^100^).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

12345
Sample Output:

one five

tip

求位数上数字的和。

anwser

using namespace std;

string GetName(int i){
    switch(i){
        case 0: return "zero";
        case 1: return "one";
        case 2: return "two";
        case 3: return "three";
        case 4: return "four";
        case 5: return "five";
        case 6: return "six";
        case 7: return "seven";
        case 8: return "eight";
        case 9: return "nine";
    }
}

int main(){
//  freopen("test.txt", "r", stdin);
    
    string N;
    int sum = 0;
    cin>>N;
    for(int i = 0; i < N.size(); i++){
        sum += (int)N[i]-48;
    }
    if (sum == 0) {
        cout<<GetName(sum);
        return 0;
    }
//  cout<<sum;
    vector<int> di;
    while(sum > 0){
        di.push_back(sum%10);
        sum/=10;
    }
    reverse (di.begin(), di.end());
    for(size_t i = 0; i < di.size(); i++){
        if (i == 0) cout<<GetName(di[i]);
        else cout<<" " << GetName(di[i]);
    }
    return 0;
}