1005 Spell It Right (20 point(s))

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本文介绍了一个程序设计挑战，要求将输入的非负整数的各位数字相加，并将和的每一位用英文单词表示。文章详细展示了如何使用C++实现这一功能，包括字符串到数字的转换、求和以及英文单词的映射。

1005 Spell It Right (20 point(s))

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (≤10100).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output:

one five

注意点

1. do-while循环

#include<iostream>
#include<cstring>
using namespace std;
string digit[10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
int arr[30];
int main(void)
{
	string in;
	cin>>in;
	int sum = 0;
	for(int i=0;i<in.length();i++){
		sum=sum+in[i]-'0';
	}
	int index = 0;
	do{
		int d = sum%10;
		arr[index] = d;
		index++;
		sum/=10;
	}while(sum>0);
	for(int i=index-1;i>=0;i--){
		if(i==0) cout<<digit[arr[i]].c_str();
		else cout<<digit[arr[i]].c_str()<<" ";
	}
	cout<<endl;
	return 0;
 }