计算两条直线的交点--C语言

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最新推荐文章于 2024-09-05 00:12:40 发布

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文章标签： c/c++

原文链接：http://www.cnblogs.com/liulei/archive/2010/06/12/1756909.html

本文提供了一段C语言代码，用于计算二维平面上两条直线的交点坐标。通过定义结构体来表示点和直线，并实现了一个函数getCross来求解交点。

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呵呵，有点急。。。

#include<stdio.h>

typedef struct point{
    int x;
    int y;
}point;

typedef struct line{
    point point1;
    point point2;
}line;

//计算两条直线的交点
point getCross(line line1, line line2)
{
    point CrossP;
    //y = a * x + b;
    int a1 = (line1.point1.y - line1.point2.y) / (line1.point1.x - line1.point2.x);
    int b1 = line1.point1.y - a1 * (line1.point1.x);

    int a2 = (line2.point1.y - line2.point2.y) / (line2.point1.x - line2.point2.x);
    int b2 = line2.point1.y - a1 * (line2.point1.x);

    CrossP.x = (b1 - b2) / (a2 - a1);
    CrossP.y = a1 * CrossP.x + b1;
    return CrossP;
}

void main()
{
    line line1;
    line line2;

    //line1
    line1.point1.x = 10;
    line1.point1.y = 10;
    line1.point2.x = 50;
    line1.point2.y = 50;

    //line2
    line2.point1.x = 2;
    line2.point1.y = 60;
    line2.point2.x = 60;
    line2.point2.y = 0;

    point CointP = getCross(line1, line2);
    printf("%d,%d\n", CointP.x, CointP.y);

}

转载于:https://www.cnblogs.com/liulei/archive/2010/06/12/1756909.html