LeetCode Construct the Rectangle

最新推荐文章于 2020-04-17 10:13:46 发布

原创最新推荐文章于 2020-04-17 10:13:46 发布 · 438 阅读

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本文介绍了一种构造矩形的算法，该算法接受一个整数面积作为输入，并返回一个尽可能接近正方形的矩形尺寸列表。文章提供了两种实现方法，一种通过逐次逼近找到最佳宽度，另一种使用平方根进行优化。

import math
class Solution(object):
    def constructRectangle(self, area):
        """
        :type area: int
        :rtype: list[int]
        """
        #x^2=area
        x = math.sqrt(area)
        if int(x) == x:
            return [int(x),int(x)]
        x = int(x+1)
        for i in xrange(x,0,-1):
            temp = area/i
            if temp * i ==area:
                return [max(temp,i),min(temp,i)]



class Solution2(object):
    def constructRectangle(self, area):
        """
        :type area: int
        :rtype: list[int]
        """
        x = int(math.sqrt(area))
        while area % x != 0:
            x-=1
            '''
            The worst scenario is when area is a huge prime number. So you always want to loop over the shorter side
            width instead of the longer side length, where width <= length.
            比如17 == 1*17
            sqrt(17)约等于4,显然便利[1~4]比较快得出结果，而[4-17]太长了
            '''
        return [area/x,x]