Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋
times.
You may assume that the array is non-empty and the majority element always exist in the array.
class Solution {
public:
int majorityElement(vector<int>& nums) {
map<int, int> num_count;
for(vector<int>::size_type i = 0; i < nums.size(); i++) {
++num_count[nums[i]];
}
map<int, int>::iterator it = num_count.begin();
for(; it != num_count.end(); it++) {
if( it->second > nums.size() / 2) {
return it->first;
}
}
return 0;
}
};
这篇博客介绍的很好,思路很多:http://www.cnblogs.com/EdwardLiu/p/4179345.html