UVA 10474 - Where is the Marble?

Where is the Marble?

Raju and Meena love to play with Marbles. They have got a lot of marbles with numbers written on them. At the beginning, Raju would place the marbles one after another in ascending order of the numbers written on them. Then Meena would ask Raju to find the first marble with a certain number. She would count 1...2...3. Raju gets one point for correct answer, and Meena gets the point if Raju fails. After some fixed number of trials the game ends and the player with maximum points wins. Today it's your chance to play as Raju. Being the smart kid, you'd be taking the favor of a computer. But don't underestimate Meena, she had written a program to keep track how much time you're taking to give all the answers. So now you have to write a program, which will help you in your role as Raju.

Input

There can be multiple test cases. Total no of test cases is less than 65. Each test case consists begins with 2 integers: N the number of marbles and Q the number of queries Mina would make. The next N lines would contain the numbers written on the N marbles. These marble numbers will not come in any particular order. Following Q lines will have Q queries. Be assured, none of the input numbers are greater than 10000 and none of them are negative.

Input is terminated by a test case where N = 0 and Q = 0.

Output

For each test case output the serial number of the case.

For each of the queries, print one line of output. The format of this line will depend upon whether or not the query number is written upon any of the marbles. The two different formats are described below:

• `x found at y', if the first marble with number x was found at position y. Positions are numbered 1, 2,...,N.
• `x not found', if the marble with number x is not present.

Look at the output for sample input for details.

Sample Input

4 1
2
3
5
1
5
5 2
1
3
3
3
1
2
3
0 0

Sample Output

CASE# 1:
5 found at 4
CASE# 2:
2 not found
3 found at 3

这题就是水题，排个序就完事了，题目的意思就是有N个大理石，每个大理石上标了数字，输入时没有特定的顺序，输入Q次待查询的数字，查询时要按照大理石上的数字大小查询，如果找到了就输出从小到大排序好之后的那个数字的位置（从1数起），题目就是这个意思，所以只要排个序就完事，代码如下，已AC

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int num[10010];
int queriy[10010];
int cmp(const void *a,const void *b)
{
	return *(int *)a-*(int *)b;
}
int main()
{
	int N,Q;
	int count=0;
	while(scanf("%d%d",&N,&Q)&&(N!=0)){
		count++;
		printf("CASE# %d:\n",count);
		memset(num,0,sizeof(num));
		memset(queriy,0,sizeof(queriy));
		for(int i=0;i<N;i++)
			scanf("%d",&num[i]);
		qsort(num,N,sizeof(num[0]),cmp);
		for(int i=0;i<Q;i++){
			scanf("%d",&queriy[i]);
			int flag=0;
			for(int j=0;j<N;j++){
				if(queriy[i]==num[j]){
					flag=1;
					printf("%d found at %d\n",queriy[i],j+1);
					break;
				}
			}
			if(!flag){
				printf("%d not found\n",queriy[i]);
			}
		}
	}
	return 0;
}