原题;
Problem Description
Current work in cryptography involves (among other things) large prime numbers and computing powers of numbers among these primes. Work in this area has resulted in the practical use of results from number theory and other branches
of mathematics once considered to be only of theoretical interest.
This problem involves the efficient computation of integer roots of numbers.
Given an integer n>=1 and an integer p>= 1 you have to write a program that determines the n th positive root of p. In this problem, given such integers n and p, p will always be of the form k to the nth. power, for an integer k (this integer is what your program must find).
This problem involves the efficient computation of integer roots of numbers.
Given an integer n>=1 and an integer p>= 1 you have to write a program that determines the n th positive root of p. In this problem, given such integers n and p, p will always be of the form k to the nth. power, for an integer k (this integer is what your program must find).
Input
The input consists of a sequence of integer pairs n and p with each integer on a line by itself. For all such pairs 1<=n<= 200, 1<=p<10<sup>101</sup> and there exists an integer k, 1<=k<=10<sup>9</sup> such that k<sup>n</sup> = p.
Output
For each integer pair n and p the value k should be printed, i.e., the number k such that k n =p.
Sample Input
2 16 3 27 7 4357186184021382204544
Sample Output
4 3 1234
代码:
- #include <iostream>
- #include <math.h>
- using namespace std;
- int main()
- {
- int n;
- double p;
- while(cin>>n)
- {
- cin>>p;
- cout<<pow(p,1.0/n)<<endl;
- }
- return 0;
- }
本文介绍了一种通过编程实现的整数根计算方法,利用数学中的幂次运算,解决密码学中涉及的大整数开方问题。具体而言,对于给定的整数n和p,寻找一个整数k,使得k的n次方等于p。
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