圆的面积
Problem Description
Input
The first line of the input is a positive integer N,then follows N lines,each line is a real number represent the radius of the circle.
Output
Output contains N lines,for each line of the input you should output one line, Case K: S,and K(count from 1)represents the number of the circle and S is the area.Keep two digits after the decimal point.
Sample Input
3 1 2 3
Sample Output
Case 1: 3.14Case 2: 12.57Case 3: 28.27
package test;
import java.util.Arrays; import java.util.Scanner;
import javax.swing.plaf.synth.SynthSpinnerUI;
public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); int n, i; n = sc.nextInt(); for(i = 0; i< n; i++) { Circle t = new Circle(); t.r =sc.nextInt(); System.out.printf("Case %d: %.2f\n", i+1, t.area(t.r)); } sc.close(); }
} class Circle{ int r; double PI=3.141592653; public double area(int r) { return r*r*PI; } }