poj1995 Raising Modulo Numbers (整数快速幂)

578 篇文章 ¥299.90 ¥399.90
26 篇文章 ¥299.90 ¥399.90
该博客详细介绍了如何解决POJ1995问题,即求解一系列乘积模M的值。通过整数快速幂算法,可以高效地计算(A1B1+A2B2+...+AHBH)mod M。样例输入和输出展示了算法的实际应用,此题源于CTU Open 1999竞赛。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Raising Modulo Numbers
Time Limit: 1000MS   Memory Limit: 30000K
Total Submissions: 7280   Accepted: 4397

Description

People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, others like using Windows, and some like difficult mathematical games. Latest marketing research shows, that this market segment was so far underestimated and that there is lack of such games. This kind of game was thus included into the KOKODáKH. The rules follow: 

Each player chooses two numbers Ai
评论 1
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值