//三种常见的前中后序(非递归遍历)
//力扣算法
结构化解题思路
//前序遍历
/**
- Definition for a binary tree node.
- struct TreeNode {
-
int val;
-
TreeNode *left;
-
TreeNode *right;
-
TreeNode() : val(0), left(nullptr), right(nullptr) {}
-
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
-
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
- };
/
class Solution
{
public:
void preorder(TreeNode root,vector&res)
{
if(root==nullptr)
{
return;
}
res.push_back(root->val);
preorder(root->left,res);
preorder(root->right,res);
}
vector preorderTraversal(TreeNode* root)
{
vector res;
preorder(root,res);
return res;
}
};
//中序遍历
/**
- Definition for a binary tree node.
- struct TreeNode {
-
int val;
-
TreeNode *left;
-
TreeNode *right;
-
TreeNode() : val(0), left(nullptr), right(nullptr) {}
-
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
-
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
- };
/
class Solution {
public:
void inorder(TreeNode root,vector&res)
{
if(root==nullptr)
{
return;
}
inorder(root->left,res);
res.push_back(root->val);
inorder(root->right,res);
}
vector inorderTraversal(TreeNode* root)
{
vector res;
inorder(root,res);
return res;
}
};
//后序遍历
/** - Definition for a binary tree node.
- struct TreeNode {
-
int val;
-
TreeNode *left;
-
TreeNode *right;
-
TreeNode() : val(0), left(nullptr), right(nullptr) {}
-
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
-
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
- };
/
class Solution {
public:
void postorder(TreeNoderoot,vector &res)
{
if(root==nullptr)
{
return;
}
postorder(root->left,res);
postorder(root->right,res);
res.push_back(root->val);
}
vector postorderTraversal(TreeNode* root)
{
vector res;
postorder(root,res);
return res;
}
};
//总结:
主要是根据的是根 左右 的顺序进行操作的过程。
//来源于力扣的解析。