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僵尸吃脑难题解析

最新推荐文章于 2020-07-14 22:29:31 发布

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本文介绍了一道关于僵尸吃脑的编程题目，通过输入僵尸所吃的脑数与所需存活的脑数来判断其是否能存活，并给出了简洁的C++代码实现。

No Brainer

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 25220		Accepted: 16459

Description

Zombies love to eat brains. Yum.

Input

The first line contains a single integer n indicating the number of data sets.

The following n lines each represent a data set. Each data set will be formatted according to the following description:

A single data set consists of a line "X Y", where X is the number of brains the zombie eats and Y is the number of brains the zombie requires to stay alive.

Output

For each data set, there will be exactly one line of output. This line will be "MMM BRAINS" if the number of brains the zombie eats is greater than or equal to the number of brains the zombie requires to stay alive. Otherwise, the line will be "NO BRAINS".

Sample Input

Sample Output

NO BRAINS
MMM BRAINS
MMM BRAINS

题意+思路：都没什么好说的，这道题太水了，都不好意思挂题解了。

AC代码如下：

#include<cstdio>
#include<cstring>
using namespace std;
int main()
{ int t,a,b;
  scanf("%d",&t);
  while(t--)
  { scanf("%d%d",&a,&b);
    if(a>=b)
     printf("MMM BRAINS\n");
    else
     printf("NO BRAINS\n");
  }
}