HDU简单题第二波 2021——2040

题意:中文题目,题意不讲赘述。

HDU 2021

Code:

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
    int wages[100],temp,n;
    while(scanf("%d",&n) == 1 && n)
    {
        int a = 0,b = 0,c = 0,d = 0,e = 0,f = 0;
        for(int i = 0; i < n; i++)
            scanf("%d",&wages[i]);
        for(int j = 0; j < n; j++)
        {
            a += wages[j]/100, temp = wages[j]%100;
            b += temp / 50; temp = temp%50;
            c += temp / 10;temp = temp%10;
            d += temp / 5, temp = temp%5;
            e += temp / 2, temp = temp%2;
            f += temp;
        }
        int x = a+b+c+d+e+f;
        printf("%d\n",x);
    }
    return 0;
}

HDU 2022

Code:

#include <iostream>
#include <cmath>
using namespace std;

int MM[101][101];
int main()
{
    int m,n,val;
    int temp,a,b;
    while(cin>>m>>n)
    {
        for(int i = 0; i < m; i++)
        for(int j = 0; j < n; j++)
        { cin>>val; MM[i][j] = val;}
        temp = 0,a = 0,b = 0;
        for(int i = 0; i < m; i++)
        for(int j = 0; j < n; j++)
        if(abs((double)MM[i][j]) > abs((double)temp)) { temp = MM[i][j], a = i, b = j;}
        cout<<a+1<<" "<<b+1<<" "<<temp<<endl;
    }
    return 0;
}

HDU 2023

Code:

#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;

int main()
{
    int m,n,num,flag;
    double score[51][6];
    double stu_aver[51],cla_aver[5];
    while(scanf("%d%d",&n,&m) == 2)
    {
        memset(cla_aver,0,sizeof(cla_aver));
        memset(stu_aver,0,sizeof(stu_aver));
        num = 0, flag = 0;
        for(int i = 0; i < n; i++)
            for(int j = 0; j < m; j++)
            {
                scanf("%lf",&score[i][j]);
                stu_aver[i] += score[i][j];
                cla_aver[j] += score[i][j];
            }
         for(int i = 0; i < n; i++)
        {
            for(int j = 0; j < m; j++)
            {
                if(score[i][j] >= cla_aver[j]/n)
                    flag = 1;
                else { flag = 0; break; }
            }
            if(flag) num++;
        }
        for(int i = 0; i < n-1; i++)
            printf("%.2lf ",stu_aver[i]/m);
            printf("%.2lf\n",stu_aver[n-1]/m);
        for(int j = 0; j < m-1; j++)
            printf("%.2lf ",cla_aver[j]/n);
            printf("%.2lf\n",cla_aver[m-1]/n);
        printf("%d\n\n",num);
    }
    return 0;
}

HDU 2024

Code:

#include <iostream>
#include <cctype>
#include <cstdio>
using namespace std;

int main()
{
    int n;
    scanf("%d",&n);
    getchar();
    while(n--)
    {
        char e,a[51];
        int flag = 1,i = 0;
        while((e=getchar()) != '\n')
        {
            if(isalpha(e) || (e >= '0'&& e <= '9') || e == '_') a[i++] = e;
            else flag = 0;
        }
        if(flag && (a[0] == '_' || isalpha(a[0])))
           printf("yes\n");
        else printf("no\n");
    }
   return 0;
}

HDU 2025

Code:

#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;

int main()
{
    char a[100],b;
    while(gets(a))
    {
        int len = strlen(a);
        int temp = 0; b = a[0];
        for(int i = 1; i < len; i++)
        if(a[i] > b) { b = a[i],temp = i;}
        for(int j = 0; j < len-1; j++)
        {
            cout<<a[j];
            if(a[j] == a[temp]) cout<<"(max)";
        }
        if(a[len-1] == a[temp])
            cout<<a[len-1]<<"(max)"<<endl;
        else cout<<a[len-1]<<endl;
    }
    return 0;
}

HDU 2026

Code:

#include <iostream>
#include <cstring>
using namespace std;

int main()
{
    char a[1000];
    while(cin.getline(a,1000))
    {
        int len = strlen(a);
        a[0] = a[0] + 'A' - 'a';
        cout<<a[0];
        for(int i = 1; i< len; i++)
        {
            if(a[i] == ' ') a[i+1] = a[i+1] + 'A' - 'a';
            cout<<a[i];
        }
        cout<<endl;
    }
    return 0;
}

HDU 2027

Code:

#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;

int main()
{
    int n,j;
    char str[101];
    scanf("%d",&n);getchar();
    for(int w = 1; w <= n; w++)
    {
        int a = 0, e = 0, i = 0, o = 0, u = 0;
        cin.getline(str,101);
        int len = strlen(str);
        for(j = 0; j < len; j++)
        {
            if(str[j] == 'a') a++;
            else if(str[j] == 'e') e++;
            else if(str[j] == 'i') i++;
            else if(str[j] == 'o') o++;
            else if(str[j] == 'u') u++;
        }
        cout<<"a:"<<a<<endl<<"e:"<<e<<endl;
        cout<<"i:"<<i<<endl<<"o:"<<o<<endl;
        if(w != n)cout<<"u:"<<u<<endl<<endl;
        else if(w == n) cout<<"u:"<<u<<endl;
    }
    return 0;
}

HDU 2028

Code:

#include <iostream>
#include <cstdio>
using namespace std;

int gcd(int a,int b)
{
    return b == 0 ? a:gcd(b,a%b);
}

int lcm(int a,int b)
{
    return a/gcd(a,b)*b;
}

int main()
{
    int a[10000],n,temp;
    while(scanf("%d",&n) != EOF)
    {
        for(int i = 0; i < n; i++)
        scanf("%d",&a[i]);
        temp = a[0];
        for(int j = 1; j< n; j++)
            temp = lcm(a[j],temp);
        printf("%d\n",temp);
    }
    return 0;
}

HDU 2029

Code:

#include <iostream>
#include <cstring>
using namespace std;

int main()
{
    int n;
    cin>>n;
    while(n--)
    {
        char a[1000];
        cin>>a;
        int flag = 1;
        int len = strlen(a);
        for(int i = 0; i <= (len-1)/2; i++)
        {
            if(a[i] != a[len-i-1]) {flag = 0;break;}
        }
        if(flag == 1) cout<<"yes"<<endl;
        else cout<<"no"<<endl;
    }
    return 0;
}

HDU 2030

Code:

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
    int num,n;
    scanf("%d",&n);
    getchar();
    while(n--)
    {
        char e; num = 0;
        while((e=getchar()) != '\n')
        {
            if(e < 0) num++;
        }
        printf("%d\n",num/2);
    }
    return 0;
}

HDU 2031

Code:

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
    int N,R,f;
    while(scanf("%d%d",&N,&R) == 2)
    {
        char a[50];
        int i = 0,flag = 1;
        if(N < 0)  { flag = -1; N = -N; }
        while(N)
        {
            f = N%R;
            if(f >= 10)
            a[i] = f-10+'A';
            else
            a[i] = f+'0';
            N = N/R; i++;
        }
        if(flag == -1) printf("-");
        for(int j = i-1; j >= 0; j--)
        printf("%c",a[j]);
        printf("\n");
    }
    return 0;
}

HDU 2032

Code:

#include <iostream>
#include <cstring>
using namespace std;

int C[101][101],n;
int main()
{
    while(cin>>n)
    {
        memset(C,0,sizeof(C));
        for(int i = 0; i< n; i++)
        {
            C[i][0] = 1;
            for(int j = 1; j<=i; j++)
            C[i][j] = C[i-1][j-1] + C[i-1][j];
        }
        for(int j = 0; j< n; j++)
        {
            for(int i = 0; i<j; i++)
            cout<<C[j][i]<<" ";
            cout<<C[j][j]<<endl;
        }
        cout<<endl;
    }
    return 0;
}
HDU 2033

Code:

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
    int hour,minute,second;
    int a[6],n;
    scanf("%d",&n);
    while(n--)
    {
        for(int i = 0; i < 6; i++)
            scanf("%d",&a[i]);
        hour = a[0] + a[3];
        minute = a[1] + a[4];
        second = a[2] + a[5];
        if(second >= 60)
        {second -= 60, minute += 1;}
        if(minute >= 60)
        {minute -= 60,hour += 1;}
        cout<<hour<<" "<<minute<<" "<<second<<endl;
    }
    return 0;
}

HDU 2034

Code:

#include <iostream>
#include <algorithm>
using namespace std;

int a[101],b[101];
int main()
{
    int n,m,k;
    while(cin>>n>>m && n+m)
    {
        for(int i = 0; i < n; i++)
            cin>>a[i];
        for(int j = 0; j < m; j++)
            cin>>b[j];
        for(int j = 0; j < m; j++)
		for(int i = 0; i < n; i++)
        if(a[i] == b[j])
        {
            k = i;
            while(k < n) {a[k] = a[k+1];k++;}
            n--;
        }
        sort(a,a+n);
        if(n == 0)cout<<"NULL";
        {
            for(int w = 0; w < n; w++)
            cout<<a[w]<<" ";
        }
        cout<<endl;
    }
    return 0;
}

HDU 2035

Code:

#include <iostream>
using namespace std;

int pow_mod(int a,int n,int m)
{
    if(n==0) return 1;
    int x = pow_mod(a,n/2,m);
    long long ans = (long long)x * x % m;
    if(n%2 == 1) ans = ans * a % m;
    return (int)ans;
}

int main()
{
    int A,B;
   while(cin>>A>>B && A+B)
    {
        int temp = pow_mod(A,B,1000);
        cout<<temp<<endl;
    }
    return 0;
}

HDU 2036

题意:多边形公式:0.5*|x1*y2-y1*x2+x2*y3-y2*x3+……+xn*y1-yn*x1|

Code:

</pre><pre name="code" class="cpp">#include <iostream>
#include <cstdio>
#include <cmath>
using namespace  std;


struct Node{
    double x,y;
}Coordinate[100];


int main()
{
    double S;
    int n;
    while(scanf("%d",&n) == 1 && n)
    {
        for(int i = 1; i <= n; i++)
            cin>>Coordinate[i].x>>Coordinate[i].y;
            S = Coordinate[n].x*Coordinate[1].y - Coordinate[n].y*Coordinate[1].x;
        for(int j = 1; j < n; j++)
        S += Coordinate[j].x*Coordinate[j+1].y - Coordinate[j].y*Coordinate[j+1].x;
        printf("%.1lf\n",S/2);
    }
    return 0;
}

HDU 2037

Code:

#include <iostream>
#include <algorithm>
using namespace std;
struct Node{
    int start,end;
    bool operator < (const Node& a) const
    {
        return end < a.end;
    }
}list[100];

int main()
{
    int n,flag,j,num;
    while(cin>>n && n)
    {
        for(int i = 0; i < n; i++)
        cin>>list[i].start>>list[i].end;
        sort(list,list+n);
        flag = 0,j = 1,num = 1;
        while(j < n)
        {
            if(list[j].start >= list[flag].end) {flag = j; j++; num++;}
            else j++;
        }
        cout<<num<<endl;
    }
    return 0;
}

HDU 2039

Code:

#include <iostream>
using namespace std;

int main()
{
    double a,b,c;
    int n;
    cin>>n;
    while(n--)
    {
        cin>>a>>b>>c;
        if(a+b > c && a+c > b && b+c > a) cout<<"YES"<<endl;
        else cout<<"NO"<<endl;
    }
    return 0;
}

HDU 2040
Code:
#include <iostream>
using namespace std;

int solve(int n)
{
    int temp = 0;
    for(int i = 1; i<n; i++)
    if(n%i == 0) temp += i;
    return temp;
}

int main()
{
    int a,b,n;
    cin>>n;
    while(n--)
    {
        cin>>a>>b;
        if(solve(a) == b && solve(b) == a) cout<<"YES"<<endl;
        else cout<<"NO"<<endl;
    }
    return 0;
}
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值