import numpy as np import pandas as pd import datetime as dt
(data['time1'] - data['time2']).dt.days, 两时间相减,时间相减不满一天向下取整
select 等价 sql
datediff('day',time2,time1)
这种只用时间中的日期计算
比如 time1 = 2020-10-25T11:43:04,time2 = 2020-09-21T14:34:43
datediff(time1,time2) = 34
而 datediff('day',time2,time1) = 33