Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree {3,9,20,#,#,15,7},
3
/ \
9 20
/ \
15 7
return its zigzag level order traversal as:
[ [3], [20,9], [15,7] ]
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<vector<int> > res; void traversal(TreeNode* root, int level) { if (0 == root) return; if (res.size() < level + 1) { vector<int> vec; vec.push_back(root->val); res.push_back(vec); } else if (level % 2 == 0) res[level].push_back(root->val); else res[level].insert(res[level].begin(), root->val); traversal(root->left, ++level); traversal(root->right, level); } vector<vector<int> > zigzagLevelOrder(TreeNode *root) { res.clear(); traversal(root, 0); return res; } };
本文介绍了一种算法,用于实现二叉树节点值的锯齿形层序遍历。从根节点开始,每经过一层,遍历的方向就会在从左到右和从右到左之间切换。通过递归方式实现,并展示了如何构造解决方案。
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