Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:Given the below binary tree and
sum
= 22,
5
/ \
4 8
/ / \
11 13 4
/ \ / \
7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
class Solution { public: vector<vector<int> > res; void judge(TreeNode* root, vector<int> vec, int last, int sum) { if (0 == root) return; if (root->left == 0 && 0 == root->right) { if (last + root->val == sum) { vec.push_back(root->val); res.push_back(vec); } } else { vec.push_back(root->val); judge(root->left, vec, last + root->val, sum); judge(root->right, vec, last + root->val, sum); } } vector<vector<int> > pathSum(TreeNode *root, int sum) { res.clear(); vector<int> tmp; judge(root, tmp, 0, sum); return res; } };
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