676. Implement Magic Dictionary

本文介绍了一种魔法字典的数据结构实现方法,通过构建字典和搜索功能,可以在给定单词中修改一个字符的情况下判断该单词是否存在于字典中。文章提供了三种不同的实现方案,并详细解释了每种方案的特点。

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Implement a magic directory with buildDict, and search methods.

For the method buildDict, you'll be given a list of non-repetitive words to build a dictionary.

For the method search, you'll be given a word, and judge whether if you modify exactly one character into another character in this word, the modified word is in the dictionary you just built.

Example 1:

Input: buildDict(["hello", "leetcode"]), Output: Null
Input: search("hello"), Output: False
Input: search("hhllo"), Output: True
Input: search("hell"), Output: False
Input: search("leetcoded"), Output: False

Note:

  1. You may assume that all the inputs are consist of lowercase letters a-z.
  2. For contest purpose, the test data is rather small by now. You could think about highly efficient algorithm after the contest.
  3. Please remember to RESET your class variables declared in class MagicDictionary, as static/class variables are persisted across multiple test cases. Please see here for more details.

知识点:set的使用,set.insert();

代码1:

class MagicDictionary {
public:
    /** Initialize your data structure here. */
    unordered_set<string> words;
    MagicDictionary() {
        
    }
    
    /** Build a dictionary through a list of words */
    void buildDict(vector<string> dict) {
        //dic.insert(dic.begin(),dict.begin(),dict.end());
        for (string &s:dict) words.insert(s);
    }
    
    /** Returns if there is any word in the trie that equals to the given word after modifying exactly one character */
    bool search(string word) {
        for (int i = 0; i < word.size(); i++) {
            char c = word[i];
            for (int j = 0; j < 26; j++) {
                if (c == j+'a') continue;
                word[i] = j+'a';
                if (words.count(word)) return true;
            }
            word[i] = c;
        }
        return false;
    }
};

/**
 * Your MagicDictionary object will be instantiated and called as such:
 * MagicDictionary obj = new MagicDictionary();
 * obj.buildDict(dict);
 * bool param_2 = obj.search(word);
 */

代码2:

class MagicDictionary {
public:
    set<string> dic;
    /** Initialize your data structure here. */
    MagicDictionary() {
        
    }
    
    /** Build a dictionary through a list of words */
    void buildDict(vector<string> dict) {
        dic.insert(dict.begin(),dict.end());
    }
    
    /** Returns if there is any word in the trie that equals to the given word after modifying exactly one character */
    bool search(string word) {
        for(string s:dic){
            if(s.size()==word.size()){
                int flag=0;
                for(int i=0;i<s.size();i++){
                    if(s[i]!=word[i]){flag++;}
                    if(flag>1){break;}
                }
                if(flag==1){return true;}
            }
        }
        return false;
    }
};

/**
 * Your MagicDictionary object will be instantiated and called as such:
 * MagicDictionary obj = new MagicDictionary();
 * obj.buildDict(dict);
 * bool param_2 = obj.search(word);
 */

代码3:

class MagicDictionary {
public:
    vector<string> dict;
    /** Initialize your data structure here. */
    MagicDictionary() {
    }
    
    /** Build a dictionary through a list of words */
    void buildDict(vector<string> dict) {
        this->dict = dict;
    }
    
    /** Returns if there is any word in the trie that equals to the given word after modifying exactly one character */
    bool search(string word) {
        for(string str:dict){
            if(judge(str,word)) return true;
        }
        return false;
    }
    
    bool judge(string str, string word){
        if(str.length() != word.length()) return false;
        int count = 0;
        for(int i=0; i<str.length(); i++){
            if(str[i] != word[i]) count++;
        }
        return count == 1? true: false;
    }
};

/**
 * Your MagicDictionary object will be instantiated and called as such:
 * MagicDictionary obj = new MagicDictionary();
 * obj.buildDict(dict);
 * bool param_2 = obj.search(word);
 */



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