Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> tmp;
void inorder(TreeNode* Node)
{
if(!Node)
return;
if(Node->left)
inorder(Node->left);
tmp.push_back(Node->val);
if(Node->right)
inorder(Node->right);
}
bool isValidBST(TreeNode* root) {
inorder(root);
for(int i = 1; i < tmp.size(); i++)
{
if(tmp[i]<=tmp[i-1])
return false;
}
return true;
}
};