#include<iostream>
#include<algorithm>
#include<iomanip>
#include<cmath>
using namespace std;
#define eps 1e-8
#define PI acos(0.0)*2.0
const int maxn=200005;
struct point{
double x,y;
}p[maxn],res[maxn];
double dis(point a,point b)
{
return sqrt(pow(a.x-b.x,2)+pow(a.y-b.y,2));
}
bool xmult(point p1,point p2,point p0)//cross product(p1-p0)X(p2-p0)
{
if(((p1.x-p0.x)*(p2.y-p0.y) >= (p2.x-p0.x)*(p1.y-p0.y)))
return false;
return true;
}
bool operator < (const point &l,const point &r)
{
return l.y<r.y || (l.y==r.y && l.x<r.x);
}
int graham(point pnt[],int n)//求凸包及凸包内点的数目
{
int i,len,top=1;
sort(pnt,pnt+n);
if(n==0) return 0;res[0] = pnt[0];
if(n==1) return 1;res[1] = pnt[1];
if(n==2) return 2;res[2] = pnt[2];
for (i = 2; i < n; i++) {
while(top &&xmult(pnt[i],res[top],res[top-1]))
top--;
res[++top] = pnt[i];
}
len = top;
res[++top] = pnt[n-2];
for (int i = n-3; i >= 0 ; i--)
{
while(top!=len &&xmult(pnt[i],res[top],res[top-1]))
top--;
res[++top] = pnt[i];
}
return top;
}
double cir_polygon(int n,point *p)//circumference
{
double cir = 0;
int i;
for (i = 0; i < n; i++)
cir += dis(p[i],p[(i+1)%n]);
return cir;
}
double area_polygon(int n,point *p)//area
{
double s1=0,s2=0;
int i;
for (i = 0; i < n; i++)
{
s1+=p[(i+1)%n].y*p[i].x;
s2+=p[(i+1)%n].y*p[(i+2)%n].x;
}
return fabs(s1-s2)/2;
}
int main()
{
int n,top;
double r;
while(cin>>n){
double ans = 0;
for (int i = 0; i < n; i++)
cin>>p[i].x>>p[i].y;
top = graham(p,n);
ans += cir_polygon(top,res);
cout<<setiosflags(ios::fixed)<<setprecision(2)<<ans<<endl;
}
return 0;
}
#include <cstdio>
#include <cmath>
#include <algorithm>
#include <iostream>
#include <cstring>
using namespace std;
const double eps = 1e-8;
const double inf = 10000000000.0;
int stk[100001], top;
struct Point {
double x, y;
} p[100001];
int dblcmp(double k) {
if (fabs(k) < eps) return 0;
return k > 0 ? 1 : -1;
}
double multi(Point p0, Point p1, Point p2) {
return (p1.x-p0.x)*(p2.y-p0.y)-(p1.y-p0.y)*(p2.x-p0.x);
}
double getDis(Point a, Point b) {
return (a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y);
}
bool cmp(const Point& a, const Point& b) {
int d = dblcmp(multi(p[0], a, b));
if (!d) return getDis(p[0], a) < getDis(p[0], b);
return d > 0;
}
int main()
{
//freopen("凸边形外壳.in","r",stdin);
int n, i, k, t;
double tx, ty;
cin >> t;
while (t --) {
memset(stk,0,sizeof(stk));
scanf("%d", &n);
tx = ty = inf;
for (i = 0; i < n; i++) {
scanf ("%lf%lf", &p[i].x, &p[i].y);
int d = dblcmp(ty-p[i].y);
if (!d && dblcmp(tx-p[i].x) > 0) {
k = i; tx = p[i].x;
} else if (d > 0) {
k = i;
ty = p[i].y;
tx = p[i].x;
}
}
if (n <= 2) {
printf ("0.0\n");
continue;
}
p[k].x = p[0].x;
p[k].y = p[0].y;
p[0].x = tx;
p[0].y = ty;
sort(p+1, p+n, cmp);
stk[0] = 0;
stk[1] = 1;
top = 1;
for (i = 2; i < n; i++) {
while (top >= 1 && dblcmp(multi(p[stk[top-1]], p[i], p[stk[top]])) >= 0) top--;
stk[++top] = i;
}
double area = 0;
for (i = 1; i < top; i++)
area += fabs(multi(p[stk[0]], p[stk[i]], p[stk[i+1]]));
printf ("%.1f\n", area/2);
}
return 0;
}