leetcode-110. Balanced Binary Tree
题目:
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
这个算法,比较简单,但是其实仔细看到话其实重复计算了。不过我没想到有什么算法可以不用重复计算的。讨论里好像也没有。这里先这样吧。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isBalanced(TreeNode root) {
if (root == null) return true;
return DFS(root)!=-1;
}
private int DFS(TreeNode root){
if(root == null) return 0;
int lh = DFS(root.left);
if(lh == -1) return -1;
int rh = DFS(root.right);
if(rh == -1) return -1;
if( lh > rh ? (lh - rh)>1 : (rh - lh)>1 ) return -1;
return Math.max(lh,rh) + 1;
}
}