There are two sorted arrays nums1 and nums2 of
size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).
Difficulty: Hard
Solution: Divide and conquer
public class Solution {
public double findMedianSortedArrays(int[] nums1, int[] nums2) {
int len1 = nums1.length;
int len2 = nums2.length;
if((len1 + len2)%2 == 1){
return (double)(findK(0, nums1, 0, nums2, (len1 + len2)/2 + 1));
}
else{
return (findK(0, nums1, 0, nums2, (len1 + len2)/2 + 1) + findK(0, nums1, 0, nums2, (len1 + len2)/2))/2.0;
}
}
public int findK(int start1, int[] nums1, int start2, int[] nums2, int k){
if(start1 >= nums1.length)
return nums2[start2 + k - 1];
if(start2 >= nums2.length)
return nums1[start1 + k - 1];
if(k == 1)
return Math.min(nums1[start1], nums2[start2]);
int A_key = start1 + k / 2 - 1 < nums1.length
? nums1[start1 + k / 2 - 1]
: Integer.MAX_VALUE;
int B_key = start2 + k / 2 - 1 < nums2.length
? nums2[start2 + k / 2 - 1]
: Integer.MAX_VALUE;
if(A_key > B_key){
return findK(start1, nums1, start2 + k/2, nums2, k - k/2);
}
else{
return findK(start1 + k/2, nums1, start2, nums2, k - k/2);
}
}
}