cf——B. Domino Effect

本文介绍了一个有趣的编程问题——Domino Show模拟。问题中,玩家Chris将多米诺骨牌按特定规则推倒,最终确定仍保持直立状态的骨牌数量。文章详细解释了问题背景及输入输出要求,并提供了一段C++代码实现解决方案。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Little Chris knows there's no fun in playing dominoes, he thinks it's too random and doesn't require skill. Instead, he decided to play withthe dominoes and make a "domino show".

Chris arranges n dominoes in a line, placing each piece vertically upright. In the beginning, he simultaneously pushes some of the dominoes either to the left or to the right. However, somewhere between every two dominoes pushed in the same direction there is at least one domino pushed in the opposite direction.

After each second, each domino that is falling to the left pushes the adjacent domino on the left. Similarly, the dominoes falling to the right push their adjacent dominoes standing on the right. When a vertical domino has dominoes falling on it from both sides, it stays still due to the balance of the forces. The figure shows one possible example of the process.

Given the initial directions Chris has pushed the dominoes, find the number of the dominoes left standing vertically at the end of the process!

Input

The first line contains a single integer n (1 ≤ n ≤ 3000), the number of the dominoes in the line. The next line contains a character strings of length n. The i-th character of the string si is equal to

  • "L", if the i-th domino has been pushed to the left;
  • "R", if the i-th domino has been pushed to the right;
  • ".", if the i-th domino has not been pushed.

It is guaranteed that if si = sj = "L" and i < j, then there exists such k that i < k < j and sk = "R"; if si = sj = "R" and i < j, then there exists such k that i < k < j and sk = "L".

Output

Output a single integer, the number of the dominoes that remain vertical at the end of the process.

Sample test(s)
input
14
.L.R...LR..L..
output
4
input
5
R....
output
0
input
1
.
output
1
Note

The first example case is shown on the figure. The four pieces that remain standing vertically are highlighted with orange.

In the second example case, all pieces fall down since the first piece topples all the other pieces.

In the last example case, a single piece has not been pushed in either direction.

 题意:点代表竖直的,R代表 右斜的,L代表左斜的,输出最后能有几个竖直的

 已知: 只要R L,并且中间的点数是 奇数个,则竖直的有 一个;

只要是LR,则 竖直的是个数是 中间的点数

#include<iostream>
#include <cstring>
#include <algorithm>
using namespace std;
char s[3005];
int main()
{
    int n;
    while(cin>>n)
    {
        cin>>s;
        int num=0;
        char str='*';
        int temp=-1;
        for(int i=0; i<n; i++)
        {
            if(s[i]=='L')
            {
                if(str=='R')
                {
                    if((i-temp-1)%2!=0)
                        num++;
                    str='*';
                    temp=i;
                }
                else
                {
                    str='L';
                    temp=i;
                }
            }
            else if(s[i]=='R')
            {
                if(str=='L'||str=='*')
                {
                    num+=i-temp-1;
                    str='R';
                    temp=i;
                }
                else if(str=='R')
                {
                    temp=i;
                }
            }
        }
        if(str!='R')
        {
            num+=n-temp-1;
        }
        cout<<num<<endl;
    }
    return 0;
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值