A. George and Sleep

最新推荐文章于 2021-12-08 09:35:52 发布

清溪浅水

最新推荐文章于 2021-12-08 09:35:52 发布

阅读量639

点赞数

CC 4.0 BY-SA版权

分类专栏： codeforces

本文链接：https://blog.youkuaiyun.com/u011470356/article/details/21236909

codeforces 专栏收录该内容

28 篇文章

订阅专栏

本文介绍了一个简单的程序，用于计算一个人入睡的具体时间。通过输入当前时间和已知的睡眠时长，程序可以推算出入睡时间，即使该时间可能发生在前一天。

George woke up and saw the current time s on the digital clock. Besides, George knows that he has slept for time t.

Help George! Write a program that will, given time s and t, determine the time p when George went to bed. Note that George could have gone to bed yesterday relatively to the current time (see the second test sample).

Input

The first line contains current time s as a string in the format "hh:mm". The second line contains time t in the format "hh:mm" — the duration of George's sleep. It is guaranteed that the input contains the correct time in the 24-hour format, that is, 00 ≤ hh ≤ 23, 00 ≤ mm ≤ 59.

Output

In the single line print time p — the time George went to bed in the format similar to the format of the time in the input.

Sample test(s)

input
05:50
05:44

output
00:06

input
00:00
01:00

output
23:00

input
00:01
00:00

output
00:01

Note

In the first sample George went to bed at "00:06". Note that you should print the time only in the format "00:06". That's why answers "0:06", "00:6" and others will be considered incorrect.

题意：输入两个时间，第一个表示醒来时的时间，第二个表示刚睡觉时候的时间，求睡了多长时间

#include<iostream>
#include <cstring>
#include <algorithm>
#include <cstdio>
#include <iomanip>
#include <cmath>
using namespace std;
int main()
{
    int h1,m1,h2,m2;
    while(scanf("%d:%d\n%d:%d",&h1,&m1,&h2,&m2)!=EOF)
    {

        int t=h1*60+m1-h2*60-m2;
        if(t<0)
        t+=24*60;
        cout<<setw(2)<<setfill('0')<<t/60<<":"<<setw(2)<<setfill('0')<<t%60<<endl;
    }
    return 0;
}