题目
There are two sorted arrays nums1 and nums2 of size m and n respectively.
Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).
You may assume nums1 and nums2 cannot be both empty.
Example 1:
nums1 = [1, 3]
nums2 = [2]
The median is 2.0
Example 2:
nums1 = [1, 2]
nums2 = [3, 4]
The median is (2 + 3)/2 = 2.5
思路

代码
class Solution:
def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float:
a=[]
for i in nums1:
a.append(i)
for i in nums2:
a.append(i)
a.sort()
l=len(a)
if l%2!=0:
return float(a[l//2])
else:
return (a[l//2-1]+a[l//2])/2

本文介绍了一个算法问题:如何找到两个已排序数组的中位数,并确保整体运行时间复杂度为O(log(m+n))。通过将两个数组合并并排序的方法给出了问题的解答。
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