真水壶-优快云博客

原创 Find Minimum in Rotated Sorted Array

Suppose a sorted array is rotated at some pivot unknown to you beforehand.(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).Find the minimum element.You may assume no duplicate exists in

2014-10-16 19:44:37 634

原创 Sudoku Solver

Write a program to solve a Sudoku puzzle by filling the empty cells.Empty cells are indicated by the character '.'.You may assume that there will be only one unique solution.A sudoku

2014-10-12 08:34:25 587

原创 Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that:Only one letter can be changed at a timeEach intermediate word must exi

2014-10-11 18:13:02 619

原创 Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that:Only one letter can be changed at a timeEach intermediate word m

2014-10-11 15:56:36 549

原创 Word Break II

Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word.Return all such possible sentences.For example, givens = "

2014-10-11 14:43:41 660

原创 Permutation Sequence

The set [1,2,3,…,n] contains a total of n! unique permutations.By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3):"123""132""213""231""3

2014-10-11 11:07:35 475

原创 Permutations II

Given a collection of numbers that might contain duplicates, return all possible unique permutations.For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2,1,1

2014-10-11 09:18:11 457

原创 Permutations

Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.If such arrangement is not possible, it must rearrange it as the lowest possible

2014-10-11 09:14:51 2267

原创 Next Permutation

Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.If such arrangement is not possible, it must rearrange it as the lowest possible o

2014-10-11 09:00:34 485

原创 Combinations

Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.For example,If n = 4 and k = 2, a solution is:[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4],]

2014-10-10 23:28:33 588

原创 Scramble String

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively.Below is one possible representation of s1 = "great": great / \ gr

2014-10-10 21:47:56 561

原创 Regular Expression Matching

Implement regular expression matching with support for '.' and '*'.'.' Matches any single character.'*' Matches zero or more of the preceding element.The matching should cover the entire input st

2014-10-10 19:44:35 536

原创 Substring with Concatenation of All Words

You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a concatenation of each word in L exactly once and without an

2014-10-10 16:12:24 552

原创 Subsets II

Given a collection of integers that might contain duplicates, S, return all possible subsets.Note:Elements in a subset must be in non-descending order.The solution set must not contain dupli

2014-10-10 13:59:25 481

原创 Multiply Strings

Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-negative.class Solution: # @param num1, a

2014-10-10 13:25:07 414

原创 Valid Number

Validate if a given string is numeric.Some examples:"0" => true" 0.1 " => true"abc" => false"1 a" => false"2e10" => trueNote: It is intended for the problem statement to be ambiguo

2014-10-10 13:12:24 482

原创 Candy

There are N children standing in a line. Each child is assigned a rating value.You are giving candies to these children subjected to the following requirements:Each child must have at least on

2014-10-10 12:57:00 466

原创 Container With Most Water

Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Fin

2014-10-10 12:13:56 427

原创 Edit Distance

Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.)You have the following 3 operations permitted on a word:

2014-10-10 09:55:52 508

原创 Interleaving String

Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.For example,Given:s1 = "aabcc",s2 = "dbbca",When s3 = "aadbbcbcac", return true.When s3 = "aadbbbaccc", r

2014-10-09 18:36:59 440

原创 Copy List with Random Pointer

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.Return a deep copy of the list.

2014-10-09 09:48:18 359

原创 Maximum Product Subarray

Find the contiguous subarray within an array (containing at least one number) which has the largest product.For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the larges

2014-09-29 15:45:11 365

原创 String to Integer (atoi)

class Solution {public: int atoi(const char *str) { if(str==NULL) return 0; long long ret=0; long long ret_max=INT_MAX; long long ret_min=-((long long)INT_MIN); bool is_positive=true;

2014-09-18 17:28:44 330

原创 Maximal Rectangle

class Solution {public: int maximalRectangle(vector > &matrix) { //转换矩阵，变成Largest Rectangle in Histogram 问题，也是醉了 if(matrix.empty()) return 0; vector unit(matrix[0].size(),0); vector

2014-09-17 21:10:25 387

原创 Trapping Rain Water

//fun...class Solution {public: int trap(int A[], int n) { if(n<3) return 0; vector left_max(n,0),right_max(n,0); //left_max[i]: 从左到i,最大值的index //right_max[i]: 从右到i,最大值的index //from le

2014-09-17 15:56:26 424

原创 Surrounded Regions

class Solution {public: void solve(vector> &board) { if(board.size()<1) return; //矩阵is_visited用于存储是否访问过 vector can_get_out(board.size()*board[0].size(),false); vector is_visi

2014-09-16 23:24:30 365

原创 Recover Binary Search Tree

/*struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) {}};*/class Solution {public: void recoverTree(TreeNode *

2014-07-12 16:52:44 508

原创 Morris遍历

解释：点击打开链接#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;struct bst_node{ int key; bst_node *left; bst_node *right; bst

2014-07-12 13:51:19 628

原创 Best Time to Buy and Sell Stock III

class Solution {public: int maxProfit(vector &prices) { int n=prices.size(); if(n==0) return 0; //从左到右遍历计算maxProfit(prices[0:i]) int *minVal=new int[n];//minVal[i] -> [0:i]区间的最小值 int

2014-07-12 11:39:08 676

原创 Best Time to Buy and Sell Stock II

class Solution {public: int maxProfit(vector &prices) { int sum = 0; for (int i = 1; i < prices.size(); i++) { int diff = prices[i] - prices[i - 1]; if (di

2014-07-12 09:52:34 360

原创 Jump Game II

class Solution {public: int jump(int A[], int n) { //table[i] 为 i jump to n-1 的最少步数 int *table=new int[n]; memset(table,-1,n*sizeof(int)); table[n-1]=0; return _jump(A,n,0,table);

2014-07-12 09:17:39 366

原创 Jump Game

class Solution {public: bool canJump(int A[], int n) { if(n==1) return true; int pre=0,cur=A[0],next=A[0]; /* pre:上一个可以到达区域的右边界 cur:由[0:pre]Jump可以到达区域的右边界 next:由[0:cur]Jum

2014-07-12 00:26:17 361

原创 Palindrome Number

class Solution {public: bool isPalindrome(int x) { if(x<0) return false; int x_cp=x; int digits=1;//纪录x的位数 while(x_cp/10>0) { digits++; x_cp=x_cp/10; } int base=pow(10,d

2014-07-11 23:52:17 357

原创 Longest Palindromic Substring

Manacher算法解释：

2014-07-11 20:44:45 384

原创 Distinct Subsequences

class Solution {public: int numDistinct(string S, string T) { if(S.size()<T.size()) return 0; int *table=new int[S.size()*T.size()]; memset(table,0,S.size()*T.size()*sizeof(in

2014-07-10 00:33:52 348

原创 Word Break

class Solution {public: bool wordBreak(string s, unordered_set &dict) { if(s.empty()) return dict.count("")==0?false:true; vector is_sep(s.size()+1,false);//is_sep[i]表示s[0,i-1]是否可分 is

2014-07-07 22:35:46 343

原创 Minimum Window Substring

class Solution {public: string minWindow(string S, string T) { if(T.empty() || S.size()<T.size()) return ""; string min_window=S; bool has_answer=false; int s_hash[256],t_hash[256];

2014-07-06 12:08:55 614

原创 Combination Sum II

class Solution {public: vector > combinationSum2(vector &num, int target) { sort(num.begin(),num.end()); vector > ret(combinationSum(num,0,target)); sort(ret.begin(),ret.end()); ret.eras

2014-07-05 23:12:14 320

原创 Combination Sum

class Solution {public: vector > combinationSum(vector &candidates, int target) { sort(candidates.begin(),candidates.end()); return combinationSum(candidates,0,target); } vector > combi

2014-07-05 21:35:57 385

原创 Word Search

class Solution {public: bool exist(vector > &board, string word) { bool *used= new bool[board.size()*board[0].size()]; for(int i=0;i<board.size();i++) { for(int j=0;j<board[0].size

2014-07-05 15:49:42 403

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